All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Shapes > Geometry
Inversion Distance (Posted on 2006-02-21) Difficulty: 3 of 5
A circle (of radius a), a line, and a point are mapped by inversion into two concentric circles and the center of those concentric circles. If the distance from the given circle's center to the line is b, then what is the distance from the point to the line?

Inversion Defined:

Let O be the center of a circle of radius k. An inversion with respect to circle O is a mapping f:R2 -> R2 such that for all P in R2 (not O), P' = f(P) lies on ray OP and
|OP'||OP| = k2.

See www.geocities.com/bractals/inv.jpg

for graphical description of inversion.

See The Solution Submitted by Bractals    
Rating: 2.8000 (5 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
re: special case? spoiler, perhaps | Comment 5 of 32 |
(In reply to special case? spoiler, perhaps by Mindrod)

The flaw in this logic is thinking that the center of a circle outside maps to the center of a circle inside.

To see this, construct the inverse circle and an interior and exterior circle which map to one another. then draw the rays which are tangent to both circles and pass through O. Now draw the arcs connecting these tangents. You'll see that the centers of these two circles are both on the same side of these arcs whereas the inner part of one circle maps to the outer part of the other meaning the centers cannot map to each other.

Edited on February 22, 2006, 2:05 am
  Posted by Eric on 2006-02-22 01:50:11

Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (1)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (14)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2024 by Animus Pactum Consulting. All rights reserved. Privacy Information