Find three positive rational numbers such that their sum is a square, and the sum of any pair exceeds the third by a square.
Classical Rules: Let a "square" be any number that is the square of a rational number.
(In reply to Full solution
by Federico Kereki)
But for x=4 and y=7, x^2 + y^2 = 65, not 63.
Also, a + b + c = 50/2 + 17/2 + 65/2 = 132/2 = 66, which I'm not sure is a square....
I got as far as the x^2 + y^2 + z^2 = t^2, but then I gave up...I seem to recall though that numbers that can be expressed as the sum of three squares all follow the same form (is it 4n+3 or something?). Something like that. Anyway, would it be possible to look for squares that also fit that form?
Posted by tomarken
on 2006-04-17 18:34:15