Find three squares such that each minus the product of the three gives a square.

Classical Rules: Let a "square" be any number that is the square of a rational number.

One possible solution is (1, 1, 1) - each minus the product of the three gives 0.

Similarly, any one square with two zeroes, or two squares and a zero will work.

I'm assuming that the question is looking for a better answer involving numbers less than 1...I'll start working on that idea now. :)

Posted by tomarken on 2006-04-20 13:14:07