I am a three digit number.
I am either divisible by 3 or by 5.
I am either divisible by 4 or by 6.
I am either divisible by 5 or by 7.
I am either divisible by 6 or by 8.
I am either divisible by 7 or by 9.
I am either divisible by 9 or by 11.

What am I?

(Note: "divisible" means leaving no remainder.)

The answer is 462.

it has to be a number which is divisible by the prime numbers i.e. 3, 7 and 11. This eliminated 5 and 9 clues 2, 4 and 6. Then as there were only even numbers left i divided the numbers left by 2 to finf the l.c.m which was three (already used).

Then multiplied 6*7*11

= 462

Posted by Thomas on 2006-05-22 18:09:44