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Happy Birthday (3) (Posted on 2006-06-09) Difficulty: 3 of 5
In Happy Birthday, the question was if there are N people in a room, what is the probability that there are at least two people in the room who share a birthday?

What if instead exactly two was required? If there are N people in a room, what is the probability that there are exactly two people in the room who share a birthday?

(Note: Assume leap year doesn't exist, and the birthdays are randomly distributed throughout the year.)

No Solution Yet Submitted by Sir Percivale    
Rating: 4.0000 (3 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Some Thoughts Puzzle Thoughts Comment 13 of 13 |
The probability that the first two have the same birthday,  but the rest do not match any of the others is
= n! * 364! / (2 * (n-2)! * 365^(n-1) * (366-n)!)


Edited on September 22, 2023, 10:22 pm
  Posted by K Sengupta on 2023-09-22 09:15:49

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