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Abramowitz And Bernhardt Families (Posted on 2006-06-21) Difficulty: 3 of 5
Two families lived next door to each other —the Abramowitzs and the Bernhardts. The total ages of the four members of the Abramowitz family amounted to one hundred years, and the total ages of the four members of the Bernhardt family also amounted to the same.

It was found in the case of each family that the sum obtained by adding the squares of each of the children's ages to the square of the mother's age equaled the square of the father's age. In the case of the Abramowitz family, however, Emmylou was one year older than her brother Eric, whereas Francine Bernhardt was two years older than her brother Frank.

What was the age of each of the eight individuals?

See The Solution Submitted by K Sengupta    
Rating: 2.0000 (1 votes)

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  Subject Author Date
AcknowledgementsK Sengupta2006-07-02 08:44:43
Solutioncomputer solved it for mecheesesteak2006-06-24 00:03:50
Solutionre: Computer Assisted Solution (spoiler)Dej Mar2006-06-21 12:10:03
SolutionComputer Assisted Solution (spoiler)Charlie2006-06-21 09:39:34
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