A= The square of the sum of the number of divisors of each of the divisors of n.
B= The sum of the cubes of the number of divisors of each of the divisors of n
Prove A=B
For example, let's have n=6. Its divisors are 1, 2, 3, and 6. These numbers respectively have 1, 2, 2, and 4 divisors. So A=(1+2+2+4)²=81 and B=1³+2³+2³+4³= 81.
