Using “Only Four” ZEROS (0) and any Mathematical Operations/Symbols [for example: 'e', 'pi',.... etc., if necessary], obtain the number 24.
This is one I came up with, although it uses the exponent 0 twice and factorial twice:
(e^0 + pi^0 + cos(0) + 0!)!
= (1 + 1 + 1 + 1)! = 4! = 24

Posted by Ender
on 20030409 02:37:40 