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The first number is 1. So, the number of 1's is 1. Hence we say that there is "One 1", which is written as "1 1" or 11. Therefore, we get the next number of the sequence as 11.
Now, in the sequence (beginning from the very first number), we have in total "Three 1's", which can be written as "3 1", thus obtaining the third term of the sequence as "31".
Again proceding as before, we see that in the entire sequence (from the first term till the third one), there are altogether "Four 1's and One 3" which is now written as "4 1 1 3", giving us the fourth term of our sequence as "4113". Using similar reasoning, we get the fifth term (which is already given) as "612314".
Applying the same logic and reasoning, we obtain the next two numbers of the given sequence as:
"8112332416" (EIGHT 1'S, ONE 2, THREE 3'S, TWO 4'S and ONE 6), and
"1113253342618" (ELEVEN 1'S, THREE 2'S, FIVE 3'S, THREE 4'S, TWO 6'S and ONE 8).
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