All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Games
Oddwins (Posted on 2006-10-03) Difficulty: 3 of 5
A game of 11 marbles wherein each player can either pick one or two marbles from the total. Starting from Player A & then Player B alternatively. This continues till all the marbles are picked. The winner is the one having odd number of marbles.

What is the strategy to be followed for Player A & B to win?. What happens for higher total number of marbles (13, 15 etc )?

No Solution Yet Submitted by Salil    
Rating: 4.0000 (1 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Some Thoughts Solution (spoiler) | Comment 1 of 11
Sorry the title is incorrect, this is not a full solution.

If the game only had 3 marbles, then A would never win.  If A takes one, B takes one, A takes one and loses.  If A takes 2, he loses as soon as B takes one.

One winning (partial) strategy would be to finish a move, while holding an odd number of marbles such that there are 3 marbles left and it's the other player's turn.  Then just take one marble on your next move and you have an even number and you win.

Edited on October 3, 2006, 4:52 pm

Edited on October 3, 2006, 4:53 pm
  Posted by Larry on 2006-10-03 16:33:48

Please log in:
Remember me:
Sign up! | Forgot password

Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (3)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Copyright © 2002 - 2020 by Animus Pactum Consulting. All rights reserved. Privacy Information