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Four Squared (Posted on 2006-10-26) Difficulty: 2 of 5
        Grid A                    Grid B      
     A   B   C   D             A   B   C   D  
   +---+---+---+---+         +---+---+---+---+
1  |   |   |   |   |      1  |14 |23 |34 |14 |
   +---+---+---+---+         +---+---+---+---+
2  |   |   |   |   |      2  |31 |42 |26 |26 |
   +---+---+---+---+         +---+---+---+---+
3  |   |   |   |   |      3  |22 |24 |44 |29 |
   +---+---+---+---+         +---+---+---+---+
4  |   |   |   |   |      4  |12 |32 |19 |16 |
   +---+---+---+---+         +---+---+---+---+
The numbers 1 to 16 are to be placed in grid A, so that consecutive numbers are not adjacent in any direction, including diagonally. Nor do they appear in the same row, column or any diagonal.

The number in each cell of grid B is the sum of the horizontal and vertical neighbors of the corresponding cell in grid A.

NB. The letters and numbers around the edge of the grid serve no purpose for the solver. They are to be used for identifying cells in the solution.

See The Solution Submitted by Josie Faulkner    
Rating: 4.4167 (12 votes)

Comments: ( You must be logged in to post comments.)
  Subject Author Date
Some ThoughtsPuzzle ThoughtsK Sengupta2022-06-06 03:30:44
re: SolutionJosie Faulkner2006-11-03 18:54:26
SolutionSolutionnikki2006-11-03 15:50:16
re: Detailed SolutionJosie Faulkner2006-10-31 05:09:45
Detailed Solutionrs2006-10-31 04:44:53
re: Solution: Took a looong time :(Josie Faulkner2006-10-31 04:08:27
Solution: Took a looong time :(rs2006-10-31 03:44:46
RE: SolutionGuest2006-10-27 19:30:06
SolutionGuest2006-10-27 19:25:21
re(3): computer solutionJosie Faulkner2006-10-27 10:31:19
re(2): computer solutionCharlie2006-10-27 09:22:36
re(2): No SubjectJosie Faulkner2006-10-27 05:45:21
re: computer solutionJosie Faulkner2006-10-26 17:42:44
re: A trivial way to solve thisJosie Faulkner2006-10-26 17:36:13
re: No SubjectJosie Faulkner2006-10-26 16:58:18
Solutioncomputer solutionCharlie2006-10-26 16:11:07
No SubjectBRYN2006-10-26 15:37:08
Some ThoughtsA trivial way to solve thisOld Original Oskar!2006-10-26 14:18:36
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