In triangle ABC, the perpendiculars from A to the internal bisectors of angles B and C meet those bisectors at X and Y. Prove that XY is parallel to BC.
(In reply to
re: Solution by Charlie)
I see that there are two right triangles sharing a base and having equal angles at the vertex, making their join an isosceles triangle.

Posted by Charlie
on 20061127 13:28:02 