All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Shapes
Map Projection (Posted on 2007-01-03) Difficulty: 2 of 5
A cartographer decides to make a map of the world using a 2-point equidistant projection.

The actual great-circle distance of any point on the map to be plotted is measured from a point on the equator at 45 degrees west longitude, and the same from 45 degrees east. These two distances are then reduced to the scale of the map. The mapping of that point is then the place on the map where the linear measures from the points representing (45 W, 0 N; 45 E, 0 N) are those reduced distances. There are, in general, two points that satisfy these conditions, so points north of the equator are plotted above the midline and points south of the equator are mapped in the bottom half of the projection.

How is the equator itself represented on the resulting map? Consider it the limiting case of non-equatorial points if you like--this might be helpful for part of the answer. If more than one shape results, specify the range of longitudes along the equator that produces each shape.

See The Solution Submitted by Charlie    
Rating: 4.2500 (4 votes)

Comments: ( You must be logged in to post comments.)
  Subject Author Date
SolutionSolutionJoel2007-01-03 19:33:41
Some Thoughtsmore thoughtsLeming2007-01-03 12:53:59
re: thoughts and maybe a partial solutionCharlie2007-01-03 10:27:02
Some Thoughtsthoughts and maybe a partial solutionLeming2007-01-03 09:20:11
Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (3)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2017 by Animus Pactum Consulting. All rights reserved. Privacy Information