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Number power (Posted on 2006-12-30) Difficulty: 3 of 5
Determine the last two and the first two digits of:

32^1+32^2+32^3+...+32^2007

No Solution Yet Submitted by atheron    
Rating: 3.0000 (1 votes)

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Solution solution to number power | Comment 1 of 4

last 2 digits are 32 and the first 2 are 10


  Posted by Dave on 2006-12-30 09:36:20
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