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Urn, urn, urn (Posted on 2007-02-20) Difficulty: 3 of 5
Before you are three urns. The first two each contain 4 white and 6 black balls. The third has 3 white and 6 black.

Take one ball from the first urn and add it to the second with out looking at it. Stir it in, then take one ball from the second and add it to the third without looking at it.

If you pick a ball from the third urn, what is the probability it will be white?

What is the least number of balls you can put in the urns (at least one black and one white in each) to make the probability at the end equal to exactly 1/3?

No Solution Yet Submitted by Jer    
Rating: 5.0000 (1 votes)

Comments: ( You must be logged in to post comments.)
  Subject Author Date
SolutionEric2007-02-20 22:30:41
Solutionpart 2: brute forceCharlie2007-02-20 17:03:26
Some Thoughtsre: Solution - Part IJyqm2007-02-20 16:46:23
Solution - Part IIhoodat2007-02-20 16:45:06
Solution - Part Ihoodat2007-02-20 15:20:10
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