All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Shapes > Geometry
Cutting Corners (Posted on 2007-02-27) Difficulty: 5 of 5
Take a polygon with area S1 and pick a number r in [0,1/2]. Take vertex A that connects sides AB and AC and add points M and N on these sides so that AM/AB=AN/AC=r. Cut corner A along MN. Cut all other corners the same way.

After repeating these steps infinite times we will get a figure with an area S2. Let's F(r)=S2/S1. It's clear that F(0)=1 and F()=0.

Questions:

(a) What is this function for square?

(b) What is this function for equilateral triangle?

(c) Is it possible to get a circle from a square or from an equilateral triangle this way?

(d) Is it possible that this function is universal for all triangles, or for all rectangles, or for all polygons?

No Solution Yet Submitted by Art M    
No Rating

Comments: ( Back to comment list | You must be logged in to post comments.)
re: interesting comparison: regular vs irregular | Comment 10 of 20 |
(In reply to interesting comparison: regular vs irregular by Charlie)

With a quadrilateral that's more irregular than a trapezoid, we do get different numbers:

                 r              area ratio
 4             0.01          0.992585184560644
 4             0.03          0.976711455250238
 4             0.05          0.959530975162394
 4             0.07          0.941145303807876
 4             0.09          0.921747612750326
 4             0.11          0.901469613592343
 4             0.13          0.881071727952944
 4             0.15          0.860101205722898
 4             0.17          0.838616102659335
 4             0.19          0.816661344413935
 4             0.21          0.794428980033211
 4             0.23          0.772013461755896
 4             0.25          0.749211518985067
 4             0.27          0.726055772435752
 4             0.29          0.702675594782874
 4             0.31          0.679331112355033
 4             0.33          0.656368891988905
 4             0.35          0.633939944936173
 4             0.37          0.61399106434176
 4             0.39          0.596606076300455
 4             0.41          0.584430752007476
 4             0.43          0.580753909783496
 4             0.45          0.585390263606205
 4             0.47          0.589820614770201

 


  Posted by Charlie on 2007-02-28 22:39:05
Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (9)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2017 by Animus Pactum Consulting. All rights reserved. Privacy Information