perplexus.info :: Numbers : Divisible by 2007

Divisible by 2007 (Posted on 2007-03-11)

Prove that A= 3410^n +3000^n -2964^n -1439^n is a multiple of 2007 for all positive integer values of n.

See The Solution Submitted by Dennis

Rating: 3.3333 (3 votes)

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Subject	Author	Date
Solution : With A Different Methodology	K Sengupta	2007-03-14 03:41:32
re: Spoiler Ahead ! (public thank you with full solution)	ken	2007-03-11 14:07:25
Spoiler Ahead !	K Sengupta	2007-03-11 11:36:50

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