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Perplexus Cryptarithm Puzzle (Posted on 2007-03-31) Difficulty: 3 of 5
The cryptarithm FLOOBLE + PUZZLE = PERPLEX has no solutions. But if the word 'PUZZLE' is included twice, then there is a solution.
How many more times can the word 'PUZZLE' appear in the addition and the cryptarithm still have a solution?

  Submitted by Brian Smith    
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Solution: (Hide)
The word 'PUZZLE' can appear 2, 3, 4 or 7 times and the cryptarithm will be solvable.
FLOOBLE + 2 * PUZZLE = PERPLEX
6255028 + 2 * 791128 = 7837284

FLOOBLE + 3 * PUZZLE = PERPLEX
4399732 + 3 * 605532 = 6216328

FLOOBLE + 4 * PUZZLE = PERPLEX
4177319 + 4 * 682219 = 6906195

FLOOBLE + 7 * PUZZLE = PERPLEX
1499246 + 7 * 307746 = 3653468

Comments: ( You must be logged in to post comments.)
  Subject Author Date
re(2): answerK Sengupta2007-04-02 11:06:36
re: answerCharlie2007-04-01 20:59:21
Some ThoughtsanswerK Sengupta2007-04-01 05:49:53
Solutioncomputer solutionCharlie2007-03-31 16:25:48
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