perplexus.info :: Numbers : A problem to end all shift-a-digit problems

A problem to end all shift-a-digit problems (Posted on 2007-03-26)

Prove that there exists no natural number such that shifting its first digit to the end, multiplies it by 5, 6, or 8.

Submitted by e.g.

Rating: 4.0000 (1 votes)

Solution: (Hide)

The simplest way to see this is to note that (1) the first digit can only be 1, and (2) no multiple of 5, 6, or 8, ends with 1.

Comments: ( You must be logged in to post comments.)

Subject	Author	Date
Puzzle Solution	K Sengupta	2022-05-11 01:35:33
re: Something of a solution (one example)	Dej Mar	2007-03-27 01:03:34
Something of a solution.	Leming	2007-03-26 13:34:01

Please log in:

Login:
Password:
Remember me:

Sign up! \| Forgot password

Search:

Search body:

Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (5)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:


perplexus dot info