A letter F is composed of 6 unit squares and two rectangles of unit width as in the figure:
Find the lengths of the two rectangles such that the center of gravity is at the center of the middle square.
(In reply to re: maybe -- numerical confirmation and question
>How does one analytically solve the two simultaneous quadratics?
I don't know: this particular one could be simplified.
Let's L1 and L2 are the lenghts of the upper and lower rectangles and
Setting the origin (0,0) at the center of the square which is left from the gravity center, we will get the following eqs:
Subtracting one from the other:
2(x^2-y^2) +3x-3y=0 then
Posted by Art M
on 2007-05-17 19:56:14