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Sequential Series (Posted on 2007-07-12) Difficulty: 3 of 5
What are the first several terms in the following sequential set.
... (29,11,5), (37,8,4), (46,8,3), (56,10,6) ...

  Submitted by jduval    
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Solution: (Hide)
(1,3,3), (2,4,3), (4,5,5), (7,6,4), (11,7,4), (16,9,3), (22,10,5), (29,11,5) ...

Whereas the first term in the series is the lazy caterers sequence (of the pattern 1,(+1),(+2),(+3)... (i.e. 1,2,4,7...)). The second is the number of letters of the next term in the sequence, and the third is the number of letters in the difference between the two terms.

Comments: ( You must be logged in to post comments.)
  Subject Author Date
Puzzle Thoughts K Sengupta2023-09-16 01:35:48
Hints/Tipsre(3): Solution (spoiler) -- Many hintsjduval2007-07-15 12:59:56
re(2): Solution (spoiler)Dej Mar2007-07-13 23:12:44
re: SolutionCorey2007-07-13 13:02:43
SolutionSolutionDej Mar2007-07-12 10:28:25
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