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Every cell in the 6x6 grid is divided into four segments, each of which contains one digit. Only one of these digits is correct; the other three are red herrings! In the three starter cells (GA, LC and LE), the rogue numbers have been shaded.

Can you shade the rogue numbers in all the other cells, so that the finished grid has the numbers 1 to 6, once only, in every row, column and coloured rectangle?

 A B C D E F G 1 5 3 2 5 3 4 1 3 6 1 4 2 3 1 4 1 2 6 5 4 1 5 2 H 4 5 2 3 4 3 5 1 2 3 6 5 2 6 1 5 2 1 3 4 1 5 4 3 I 6 1 2 3 1 5 2 6 5 4 3 6 3 2 5 1 6 2 4 5 3 2 5 2 J 6 1 4 5 1 3 5 6 2 3 1 3 2 3 1 6 4 5 3 1 5 6 5 2 K 5 4 3 1 5 4 2 3 1 2 3 4 6 1 4 5 2 6 5 4 3 4 5 6 L 1 2 5 4 3 4 6 2 6 1 2 1 3 6 1 2 5 2 1 5 2 3 6 4

 See The Solution Submitted by Josie Faulkner Rating: 4.6000 (10 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
 Solution | Comment 11 of 13 |

The solution is given in terms of the following grid:

1...4...5...6...3...2
5...2...3...4...1...6
6...3...1...2...4...5
2...6...4...3...5...1
4...1...6...5...2...3
3...5...2...1...6...4

*** Of course, I agree that this problem is among the very best exercises dealing extensively with shapes and logic submitted by JF.

Edited on August 13, 2007, 4:10 am
 Posted by K Sengupta on 2007-08-13 04:08:59

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