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Getting The Bases With 2007? (Posted on 2007-09-09)

Does there exist any positive integer base N ≥ 8 such that 2007 is a perfect cube?

See The Solution Submitted by K Sengupta

Rating: 3.0000 (1 votes)

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another solution

| Comment 3 of 4 |

Wouldn't it just be easier to notice that N^3 < 7 + 2*N^3 < (N+1)^3 = N^3 + 3*N^2+3*N+1 ?

Posted by bubu on 2007-10-18 13:11:30

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