All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Shapes > Geometry
Find the Ratio (Posted on 2007-08-20) Difficulty: 2 of 5
I (radius=r) is the incircle of triangle ABC (right angled at B) and O (radius=R) is another circle which touches the extended side BC and AC. Find the ratio (R/r) if the point of intersection of circles I and O is midpoint of AC.

  Submitted by Praneeth    
Rating: 3.2500 (4 votes)
Solution: (Hide)
3+2*√2
The tangents from an external point to the circle are equal. As Incircle touches hypotenuse at midpoint, ABC is isosceles right angledtriangle. => BC=AC/√2
Draw perpendiculars from I and O on to BC and points of intersection beP and Q respectively. Draw perpendicular from I to OQ to meet at R.
http://perplexus.info/show.php?pid=5713&cid=38269 Now BC=r+PC, AC=2*PC.
=> (r+PC)*√2=2*PC => PC=(√2 +1)*r --(1)
Consider triangle IOR
IR=2*PC
IO=r+R
OR=R-r(Assume R>r)
As it is aright angled triangle,
4*PC˛+(R-r)˛=(R+r)˛
=> PC = √(R*r)
Substitute this in eq(1)
√(R*r)=(√2 +1)*r
=> √(R/r)=√2 +1
=> R/r = 3+2*√2.
Other solutions are given in comments by Bractals and Charlie.

Comments: ( You must be logged in to post comments.)
  Subject Author Date
AnswerK Sengupta2008-08-10 06:34:25
SolutionsolutionCharlie2007-08-20 11:48:05
SolutionSolutionBractals2007-08-20 11:23:46
Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (5)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2018 by Animus Pactum Consulting. All rights reserved. Privacy Information