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oddmodonacci (Posted on 2007-09-04) Difficulty: 3 of 5
0,1,__,3,5,__,0,6,__,17,5,...

  Submitted by jduval    
Rating: 4.4286 (7 votes)
Solution: (Hide)
Fibonacci(nth term)mod(nth odd)==>
1 mod 1, 1 mod 3, 2 mod 5, 3 mod 7, 5 mod 9, 8 mod 11,...
or 0,1,2,3,5,8,0,6,0,17,5,...

Comments: ( You must be logged in to post comments.)
  Subject Author Date
SolutionPuzzle SolutionK Sengupta2022-09-11 01:20:26
Hints/Tipsre: My thoughtsjduval2007-09-07 14:18:41
Some ThoughtsMy thoughtsGuest2007-09-06 17:47:03
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