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 Two Triangles Divided (Posted on 2007-12-16)
There are two triangles ABC, and A'B'C'. The bases are AB and A'B'.

Triangle ABC has an altitude drawn from C to AB, meeting the base at point P. This altitude divides the triangle into two unequal right triangles.

Triangle A'B'C' also has a point, P' on its base, with a line segment connecting it to vertex C', but chosen so that angle A'P'C' is 60°, with the resulting triangle A'P'C' though, not being equilateral.

All eight line segments are of integer length, and each triangle has a perimeter less than 50. The bases, AB and A'B', are the longest sides in each of the two respective original triangles, and they differ by 1 unit in length.

• What are the dimensions of the triangles ABC and A'B'C'?
• What are the lengths of CP and C'P'?

 See The Solution Submitted by Charlie No Rating

Comments: ( You must be logged in to post comments.)
 Subject Author Date re: Answer (Solution) DJ 2007-12-17 21:45:11 Solution Dej Mar 2007-12-17 21:03:37 Answer DJ 2007-12-17 17:30:26 Partial Solution Praneeth 2007-12-17 01:43:57
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