You sit down with a well mixed deck containing A cards marked "+" and B cards marked "—". You may draw cards from this deck as long as you want, i.e., you can stop playing at any point. Each time you draw a + card you are given $1 and each time you draw a — card you have to pay $1. Cards are not
replaced after having been drawn.
What would be a fair amount to pay for the right to play (i.e., what is the expected payoff) and under what circumstance should a player cease drawing?
Many people have offered "solutions" based on the assumption that a player should stop drawing as soon as there is an equality between the number of + and - cards remaining.
No one has attempted to justify this assumption, and it is easily seen to be wrong by considering the trivial case A=B=1. Following a strategy of drawing until you reach the + card, a player has a 50% chance of winning $1 and a 50% chance of breaking even.
We can already say some things about the "fair price to play function", W(A,B). For instance
W(1,1) = .5
W(A,0) = A
W(0,B) = 0
The solution would express W in terms of A and B. Cases like these are useful as "sanity checks" on the form of the function W.
Edited on March 12, 2008, 10:23 am
Posted by FrankM
on 2008-03-12 10:10:48