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Sum of Squares (Posted on 2008-09-26) Difficulty: 3 of 5
The sum of n+1 consecutive squares, beginning with the square of
n(2n+1), is equal to the sum of the squares of the next n consecutive integers.

   n=1      32 + 42 = 52
   n=2      102 + 112 + 122 = 132 + 142
      .
      .
      .
Prove that the proposition holds for all integers greater than zero.

See The Solution Submitted by Bractals    
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  Subject Author Date
more generalized solutionDaniel2008-09-27 11:55:04
SolutionSolutionK Sengupta2008-09-27 06:31:01
re(3): solution (spoiler) -- print SIGMADaniel2008-09-26 19:27:47
re(2): solution (spoiler) -- print SIGMAed bottemiller2008-09-26 19:17:37
re: solution (spoiler)Daniel2008-09-26 12:39:31
solution (spoiler)Daniel2008-09-26 12:35:54
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