All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Numbers
Arranging numbers in a row (Posted on 2008-11-20) Difficulty: 2 of 5
How many numbers, from 1 to 50 (both included) can you arrange in a row (one of each) so that each one, except the first and the last, is the sum or difference of its two neighbours?

Example: 3, 10, 7, 17, 24, 41.

10 = 3+7, 7 = 17-10, 17 = 24-7, 24 = 41-17.

See The Solution Submitted by pcbouhid    
Rating: 2.3333 (3 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Question re: computer solution ---- can you check, please? | Comment 5 of 12 |
(In reply to computer solution by Charlie)

41 / 25 / 16 / 9 / 7 / 2 / 5 / 3 / 8 / 11 / 19 / 30 / 49.

Starting from the middle (5) we have the "right leg" exactly +1, +1, +2, +3, +5, +8 than the corresponding number in "left leg".

These are the first Fibonacci numbers. Coincidence, or we could imply that if we extend the numbers to 80, the maximum sequence will be:

66 / 41 / 25 / 16 / 9 / 7 / 2 / 5 / 3 / 8 / 11 / 19 / 30 / 49 / 79?

 

 

Edited on November 20, 2008, 9:32 pm
  Posted by pcbouhid on 2008-11-20 21:30:12

Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (1)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (14)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2024 by Animus Pactum Consulting. All rights reserved. Privacy Information