Each triangular section was numbered variously 1 through 9, with every digit except 1 and 9 appearing twice on each die (but on different faces). On each face, the center space was the sum of two of its corners, except on one face where it was the difference, and the centers comprised 4 consecutive numbers. The corners on one face summed to a square, on another to a prime number and the corners on the remaining two faces were each comprised of consecutive numbers.

I also noticed that only three odd numbers occurred around two of the vertices while only even numbers occurred around the other two, and in each case the three numbers were different. The product of one set of even numbers was a cube, the sum of the other three even numbers also equalled the sum of the digits in their product, and only one odd number was duplicated between the two odd vertices. Further, the sums of the three numbers at each vertex result in 4 more consecutive numbers.

What were the numbers on each face and how were they arranged?

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For convenience, present the solution as an unfolded die thusly. Your arrangement may vary from the solution (what you indicate as the center face, for example), but the contents and relationships of the faces won't change.

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