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Mirrors in a Hex (Posted on 2009-05-08) Difficulty: 3 of 5
Six vertical mirrors are arranged to form a regular hexagon with only a small gap (of negligible size) at each vertex. A beam of light is shone through one of these gaps toward the one directly opposite, through which it exits.

However, the beam can be aimed slightly off this direct route to the other side, so that it is reflected off each of the mirrors exactly once before finally exiting the arrangement through that same opening opposite its entrance.

What is the smallest angle off of straight across which will make this possible?

  Submitted by Charlie    
Rating: 3.0000 (1 votes)
Solution: (Hide)
arctan(sqrt(3)/11), or about 8.94827556462713 degrees, as seen on the diagram below.

The vertices are labeled in hexagons only according to the reflection through the side actually traversed in the diagram, or reflected from in the actual mirror situation, that is, in the order DE, BC, AF, CD, EF, AB. Some hexagons not traversed have vertices whose labels are from adjoining hexagons.

Based on Enigma No. 1532, "Just Reflecting", by Bob Walker, New Scientist, 14 February 2009, page 26.

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  Subject Author Date
SolutionSolutionBractals2009-05-08 15:03:37
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