You are blindfolded before a table. On the table are a very large number of pennies. You are told 128 of the pennies are heads up and the rest are tails up.

How can you create two subgroups of pennies, each with the same number of heads facing up?

(In reply to Clarification: by Gamer)

Yeah.. I looked at SK's solution much too quickly when on my lunch break at school. Saying to turn over every penny "one by one" implied that at some point, the two groups would have the same number of heads. It would have been more clear just to say, take 128 of the pennies and turn each one over, after which both groups will have the same number of heads.
So, his solution is fine, of course, the wording just muddled up for me at first glance.

Posted by DJ on 2003-10-14 18:03:14