Solve this alphametic, where each of the capital letters in bold denotes a different decimal digit from 0 to 9. None of the numbers can contain any leading zero.
3√(HOW)+ 3√(AND) = 3√(WHEN)
(In reply to
re: two views by Charlie)
At review I had asked about integer values of the radicals but didn't get a response which didn't really worry me.
Charlie, thanks for that response, I have a general concept to what you refer. And if I fully understand the matter then if we had infinite precision then we'd neveer get a result? If that is the case then it seems that a level of precision have been built into the problem, is that true?
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Posted by brianjn
on 2009-07-30 22:16:14 |
re(2): two views
