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Pandigital Processed Primes (Posted on 2009-06-27) Difficulty: 3 of 5
Three prime numbers, p1, p2, p3, are processed by multiplying the first by 7, the second by 8 and the third by 9, so you have

7p1, 8p2 and 9p3.

and it's found that

7p1 < 8p2 < 9p3.

Taken together, 7p1, 8p2 and 9p3 use all nine digits 1 - 9 exactly once each, with no zeros.

Also, the product of 7p1, 8p2 and 9p3 is a 9-digit number containing each digit 1 - 9.

What are the three processed primes, 7p1, 8p2 and 9p3?

See The Solution Submitted by Charlie    
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  Subject Author Date
solutionDaniel2009-06-28 09:39:37
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