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Square String Settlement (Posted on 2010-01-28) Difficulty: 2 of 5
All the positive perfect squares 1, 4, 9, 16, 25.... are written in strictly ascending order of magnitude and without the commas and spaces, resulting in the following infinite string:

149162536496481100121144......

Reading left to right, what is the 2010th digit in the above pattern?

See The Solution Submitted by K Sengupta    
Rating: 3.0000 (1 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Solution If I counted right... | Comment 1 of 8
My answer is 6.

I made a chart:
Digits Range Number Count Cumulative
1       1to3      3           3        3
2       4to9      6           12      15
3      10to31    22         66      81
4      32to99    68        272    353
5      100to316 217      1085  1438
6 digits squares will take this over 2010
2010 - 1438 = 572 more digits
572/6 = 95 r 2
316 + 95 = 411
We need 2 digits into the next square
412^2 = 169744 the second digit of this is 6.

  Posted by Jer on 2010-01-28 11:44:39
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