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Infinitely Continued III (Posted on 2010-02-04) Difficulty: 3 of 5
Evaluate:

√(6+2√(7+3√(8+4√(9+5√(10+ ....)))))

No Solution Yet Submitted by K Sengupta    
Rating: 4.0000 (1 votes)

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Question Is my reasoning valid? | Comment 2 of 7 |
Define a function f(x) = √((x+2)+(x-2)√((x+3)+(x-1)√((x+4)+x√((x+5)+(x+1)√((x+6)+ ....)))))

We wish to find f(4)

f(x)^2 = (x+2)+(x-2)√((x+3)+(x-1)√((x+4)+n√((x+5)+(x+1)√((x+6)+ ....))))
f(x)^2 = (x+2)+(x-2)*f(x+1)

f(x+1) = (f(x)^2 - x - 2)/(x-2)

This doesnt feel like a valid argument but the above works if f(x)=x

x+1 = (x^2 - x - 2)/(x-2)
x+1 = (x+1)(x-2)/(x-2)
x+1 = x+1

So f(4)=4

Edited on February 4, 2010, 5:00 pm
  Posted by Jer on 2010-02-04 15:17:51

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