Make a list of distinct positive integers that are obtained by assigning a different base ten digit from 1 to 9 to each of the capital letters in this expression.
(A+B)*C + (D–E)/F + (GH)*I
What are the respective minimum and maximum positive palindromes from amongst the elements that correspond to the foregoing list?
As a bonus, what are the respective minimum and maximum positive
tautonymic numbers that are included in the list? How about the respective maximum and minimum prime numbers?
(In reply to
re(2): Primes by Ady TZIDON)
Sorry; this was a fault in my manual annotation of the operation symbols on the results. I had placed a multiplication * where in fact there was in the original problem and in the computer calculations a division. The correct table for primes should be
(3+7)*2+(9-4)/5+(1^6)*8 =29
(3+7)*2+(9-5)/4+(1^6)*8 =29
(3+8)*2+(9-4)/5+(1^7)*6 =29
(3+8)*2+(9-5)/4+(1^7)*6 =29
(4+7)*2+(3-9)/6+(1^5)*8 =29
(4+7)*2+(6-9)/3+(1^5)*8 =29
(4+7)*2+(8-3)/5+(1^9)*6 =29
(4+7)*2+(8-5)/3+(1^9)*6 =29
(5+6)*2+(3-7)/4+(1^9)*8 =29
(5+6)*2+(4-7)/3+(1^9)*8 =29
(5+7)*2+(9-3)/6+(1^8)*4 =29
(5+7)*2+(9-6)/3+(1^8)*4 =29
(5+8)*2+(3-9)/6+(1^7)*4 =29
(5+8)*2+(6-9)/3+(1^7)*4 =29
(6+5)*2+(3-7)/4+(1^9)*8 =29
(6+5)*2+(4-7)/3+(1^9)*8 =29
(6+7)*2+(3-8)/5+(1^9)*4 =29
(6+7)*2+(5-8)/3+(1^9)*4 =29
(7+3)*2+(9-4)/5+(1^6)*8 =29
(7+3)*2+(9-5)/4+(1^6)*8 =29
(7+4)*2+(3-9)/6+(1^5)*8 =29
(7+4)*2+(6-9)/3+(1^5)*8 =29
(7+4)*2+(8-3)/5+(1^9)*6 =29
(7+4)*2+(8-5)/3+(1^9)*6 =29
(7+5)*2+(9-3)/6+(1^8)*4 =29
(7+5)*2+(9-6)/3+(1^8)*4 =29
(7+6)*2+(3-8)/5+(1^9)*4 =29
(7+6)*2+(5-8)/3+(1^9)*4 =29
(8+3)*2+(9-4)/5+(1^7)*6 =29
(8+3)*2+(9-5)/4+(1^7)*6 =29
(8+5)*2+(3-9)/6+(1^7)*4 =29
(8+5)*2+(6-9)/3+(1^7)*4 =29
(4+6)*5+(3-1)/2+(8^9)*7 =939524147
(4+6)*5+(3-2)/1+(8^9)*7 =939524147
(6+4)*5+(3-1)/2+(8^9)*7 =939524147
(6+4)*5+(3-2)/1+(8^9)*7 =939524147
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Posted by Charlie
on 2010-03-24 00:47:38 |
re(3): Primes
