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Cantilever Structure (Posted on 2010-02-26) Difficulty: 3 of 5






The cantilever structure shown in the figure consists of 4n-1 struts of the same length plus one that is half that length. Each strut can handle a maximum tension force T before it will snap and a maximum compression force C before it will buckle. The structure is connected to a wall at points B and C. A weight W is attached at point A. The weight W is increased until two struts fail - one from tension and the other from compression.

What is the value of the ratio C/T if n = 25?

Consider the struts as weightless.

See The Solution Submitted by Bractals    
Rating: 3.0000 (1 votes)

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Solution Soultion (spoiler) | Comment 1 of 6

The answer is that  C/T=[n-sin(30 deg)]/n

Given the formulation of the problem, one can only assume that each member of the truss is a two-force member and can only support forces along its length.  If one then considers the entire structure, and determines the equilibrium force at the wall attachments, at C there can only exist a horizontal force, acting to the right on the truss.  From a summation of moments, it can be shown that the magnitude of this force must be W*n/cos(30 deg) tension at A.  For equilibrium to exist, the force at B on the truss must be and equal and opposite force to that at A acting to the left of magnitude W*n/cos(30deg) and  a vertical force of W acting upwards.  Since all the truss segments are two force members, only the angular truss (i.e. not the horizontal member) at B can act to support the vertical force W.  Since it is placed at an angle of 30 degrees to the vertical, the total force in this member is therefore W/cos(30 deg) compression.  It follows then that the horizontal member at B must support the balance of the reaction to the equal and opposite horizontal force of W*n/cos(30 deg) (compression) which equals W*tan(30) in the angular member and W*(n/cos(30)-tan(30)) in the horizontal member (compression).  This latter value for the horizontal member at B is a larger compression force than the value in the angular member.  Therefore the ratio of Cmax/Tmax = [n/cos30-tan(30)]/[n/cos(30)], which simplifies to the above answer.


  Posted by Kenny M on 2010-02-26 22:39:04
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