perplexus.info :: Numbers : Sum Celebrity Concerns

Sum Celebrity Concerns (Posted on 2010-07-25)

Solve separately each of these base ten alphametics. None of the numbers (including those covered under functions) corresponding to any of the following alphametics can contain leading zero.

(I) THOMAS+MALTHUS+1766+1834+RR=RRRRRRR, whenever MOST is divisible by 23.

(II) DINAH+SHORE+1916+1994+TT=TTTTT, where:
sod(DEAR)/sod(HEARTS) = 2/3 and, dr(ROSE) = 4

(III) BENNY+BELL+1906+1999+BBB= DR+DE+MENTO, where:
sod(TRY)/sod(BLEND) = 4/9

Note:sod(x) denotes the sum of digits of x and dr(x) denotes the digital root of x.

Submitted by K Sengupta

Rating: 5.0000 (1 votes)

Solution: (Hide)

(i)
O M R A H S U L T 0 1 2 3 4 5 6 7 8
840135+1378465+1766+1834+22= 2222222
1058/23 =46, so that MOST is divisible by 23.
(ii)
A D S H T O I E R N 0 1 2 3 4 5 6 7 8 9
16903+1916+1994+44 = 44444
sod(1708)/sod(370842) = 16/24 = 2/3
dr(8527) = dr(22)= 4
(iii)
O Y N T L B M E R D 0 1 2 3 4 5 6 7 8 9
57221+5744+1906+1999+555 =98+97+67230
sod(381)/sod(54729) = 12/27= 4/9

Comments: ( You must be logged in to post comments.)

Subject	Author	Date
No Subject	K Sengupta	2024-02-03 02:42:03
No Subject	K Sengupta	2024-02-03 02:41:52
No Subject	K Sengupta	2022-03-28 00:35:39
No Subject	rrobert	2022-03-28 00:16:49
re: No Subject	Naveen Kumar	2022-01-03 04:42:03
No Subject	Yuli Lawrence	2021-04-29 05:09:01
No Subject	Dej Mar	2010-07-25 21:27:32
computer solution part 2	Charlie	2010-07-25 13:54:53
computer solution for part 1	Charlie	2010-07-25 13:14:22

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