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Flying Low (Posted on 2010-08-05) Difficulty: 2 of 5
Substitute each of the letters by a different digit from 0 to 9 to satisfy this system of alphametic equations. None of the numbers as well as none of the exponents contains a leading zero.
  • (DID)W = FXA, and:
  • (FLY)A = YLI, and:
  • (LOW)O = ILT

No Solution Yet Submitted by K Sengupta    
Rating: 2.0000 (1 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Clarification? | Comment 1 of 5

I understand "FLY" would be (100*F)+(10*L)+Y, but how are the multiletter exponents to be read?

Does XA mean (X * A)  or  ((10*X) + A)?  Please clarify unless this ambiguity is part of the puzzle (e.g. only one interpretation would have a solution).

This depends upon the conventions in use for alphametics, which are not standardized. (In any case, rather large exponents! -- perhaps best left to those with Mathematica.)

 


  Posted by ed bottemiller on 2010-08-05 11:42:38
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