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Distance = Inradius (Posted on 2010-10-14) Difficulty: 3 of 5
M is the midpoint of the side BC of triangle ABC, the center of whose incircle is denoted by O. AH is perpendicular to BC, and the line MO intersects AH at the point E. It is known that: |AB| ≠ |AC|.

Prove that the distance AE is equal to the radius of the incircle.

See The Solution Submitted by K Sengupta    
Rating: 3.5000 (2 votes)

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  Subject Author Date
SolutionSolutionBractals2010-10-14 15:43:33
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