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 Sum Celebrity Concerns II (Posted on 2010-10-22)
Solve separately each of these base ten alphametics. None of the numbers (including those covered under functions) corresponding to any of the following alphametics can contain leading zero.

aaa
aa(I)aaaaaaHENRY
aaa+aaaaWOTTON
aaa+aaaaaaia1568
aaa+aaaaaaia1639
aaa+aaaaaaaaSSS
aaa=aaaaiSSSSSS,aaawhenever NOTEWORTHY is divisible by 19.

a (II) aaNELLIE
aaa+aaaMELBA
aaa+aaaaa1861
aaa+aaaaa1931
aaa+aaaaaaaaC
aaa+aaaaaaaaR
aaa+aaaaaaaaU
aaa=aaRRRRRR,aaawherea sod(CLAIR)/sod(LUNE) = CU/BE

(III) MISSSSS = MARILYN
aaaaaaaaaaaa+ aiMONROE
aaaaaaaaaaaa+ aaaaa1926
aaaaaaaaaaaa+ aaaaa1962
aaaaaaaaaaaa+ aaaaaaaiM
aaaaaawhere:
aaaaaaaaaaAM = sod(NORMA)
aaaaaaaaaaaand aadr(MARRY) + dr(MILLIONAIRE) = 15

Note: sod(x) denotes the sum of digits of x and, dr(x) denotes the digital root of x.

 No Solution Yet Submitted by K Sengupta No Rating

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 solution Comment 1 of 1
Part I

70825
+ 369968
+    1568
+    1639
+      444
= 444444

-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+

Part II

584428
+   78430
+     1861
+     1931
+          1
+          6
+          9
= 666666

-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+

Part III

4237859
+    469360
+       1926
+       1962
+            4
=  4711111

 Posted by Justin on 2011-10-23 02:08:28

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