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Bisector Inequality (Posted on 2010-08-19) Difficulty: 3 of 5

In ΔABC the bisector of /BAC intersects side BC in point D 
and the bisector of /ACB intersects side AB in point E. 
Prove that

        /ABC > 60°  ==>  |AE| + |CD| < |AC|.

See The Solution Submitted by Bractals    
Rating: 4.0000 (1 votes)

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  Subject Author Date
SolutionSolutionHarry2010-08-23 23:00:34
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