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p^7 + q^3 = r^2 (Posted on 2011-01-09) Difficulty: 3 of 5
Determine all possible triplets (p, q, r) of positive integers that satisfy this equation:

p7 + q3 = r2, whenever gcd (p, q, r) = 1

  Submitted by K Sengupta    
Rating: 5.0000 (1 votes)
Solution: (Hide)
(p,q,r) = (1,2,3), and (2,17,71) are the only possible solutions.

For an explanation, refer to the analytic solution submitted by broll in this location.

Comments: ( You must be logged in to post comments.)
  Subject Author Date
Some Thoughtssome thoughtsbroll2011-01-10 04:16:12
Some Thoughtsre: sub-spoiler--another, via computerCharlie2011-01-09 18:04:51
Some Thoughtssub-spoilerAdy TZIDON2011-01-09 12:26:48
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