All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Probability
Pandigital and divisible (Posted on 2010-12-26) Difficulty: 2 of 5
What percentage of pandigital* numbers is divisible by 990 ?


*A pandigital number consists of 10 distinct digits.

Try to solve analytically.

  Submitted by Ady TZIDON    
No Rating
Solution: (Hide)
( 11* 5!* 4!)/(9!* 9) = 0.9700176% if no leading zeroes are allowed.
see Dan Rosen's posts.
Replace the 9*9! by 10! for the case of leading zeroes allowed.

Comments: ( You must be logged in to post comments.)
  Subject Author Date
SolutionCorrection of analytical solutionDan Rosen2011-04-01 23:20:55
SolutionAnalytical SolutionDan Rosen2011-04-01 11:37:56
Hints/Tipsre: computer solution ahint for ChAdy TZIDON2010-12-26 20:17:29
Solutioncomputer solutionCharlie2010-12-26 19:45:19
Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (1)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2017 by Animus Pactum Consulting. All rights reserved. Privacy Information