Suppose ABC is an equilateral triangle and P is a point inside the triangle, such that PA = 3 cms., PB = 4 cms., and PC = 5 cms.
Then find the length of the side of the equilateral triangle.
By drawing circles of radii 3, 4, and 5 and then moving them slowly along 30, 150, and 270 degree lines in AutoCAD until the three circles intersect and then measuring the distances between their centers, I came up with about 6.7524. Not very complex, but somewhat effective?
Posted by corey
on 2003-12-18 14:39:16