Suppose ABC is an equilateral triangle and P is a point inside the triangle, such that PA = 3 cms., PB = 4 cms., and PC = 5 cms.
Then find the length of the side of the equilateral triangle.
s=side of triangle
in PCB and PAC - theorem of cosinus:
the result is an equation (bi-square):
s^4 - 50s^2 + 193 = 0
the unique solution satisfying the side of a triangle is:
Posted by luminita
on 2004-01-08 08:44:39