All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Logic
Mutually friendly 2 (Posted on 2011-07-01) Difficulty: 3 of 5
In Mutually friendly, we proved that if any two people are either friends or strangers, then any group of six people either contains 3 mutual friends or 3 mutual strangers, or both. Now, they can also be enemies.

Suppose that any two people are either friends, enemies, or strangers. Prove that any group of 17 people either contains 3 mutual friends, 3 mutual enemies, or 3 mutual strangers.

See The Solution Submitted by Math Man    
Rating: 5.0000 (1 votes)

Comments: ( You must be logged in to post comments.)
  Subject Author Date
SolutionConfirmed: 17 is the minimumSteve Herman2011-07-02 22:18:46
SolutionProof (spoiler)Steve Herman2011-07-01 17:31:51
re: The enemy of my enemy is my friend?Math Man2011-07-01 17:21:26
Some ThoughtsThe enemy of my enemy is my friend?Steve Herman2011-07-01 14:43:25
Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (3)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2024 by Animus Pactum Consulting. All rights reserved. Privacy Information