All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Numbers
A beast in a pie (Posted on 2012-05-13) Difficulty: 3 of 5
The first n digits of the decimal expansion of PI (=3.14159265...) add up to 111*m, such that (2*m)2=n .

Find n & m .

No Solution Yet Submitted by Ady TZIDON    
No Rating

Comments: ( Back to comment list | You must be logged in to post comments.)
Solution computer solution Comment 1 of 1
   10   point 224
   20   Pi=cutspc(str(#pi)):Pi=left(Pi,1)+mid(Pi,3,*)
   30   for N=1 to 1000
   40     Tot1=Tot1+val(mid(Pi,N,1)):Tot2=Tot2+val(mid(Pi,N+1,1))
   50     if Tot1 @ 111=0 then
   60       :M=Tot1//111
   70       :if 4*M*M=N then print N,M,Tot1,"tot1"
   80     if Tot2 @ 111=0 then
   90       :M=Tot2//111
  100       :if 4*M*M=N then print N,M,Tot2,"tot2"
  110   next N
OK
run
Words for fractionals 224 (Decimals for display 1078)
 144     6       666    tot2
OK

This shows that n = 144 and m = 6, making 111*m = 666, the number of the beast according to Revelation (the Apocalypse), the last book of the New Testament.

The notation "tot2" indicates that the counting for n begins at the 1 after the decimal point, rather than the 3 at the beginning of pi.

The 144 digits involved that add up to 666 are given by:

?mid(pi,2,144)
14159265358979323846264338327950288419716939937510582097494459230781640628620899
8628034825342117067982148086513282306647093844609550582231725359

  Posted by Charlie on 2012-05-13 12:51:51
Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (2)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2017 by Animus Pactum Consulting. All rights reserved. Privacy Information