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 A beast in a pie (Posted on 2012-05-13)
The first n digits of the decimal expansion of PI (=3.14159265...) add up to 111*m, such that (2*m)2=n .

Find n & m .

 No Solution Yet Submitted by Ady TZIDON No Rating

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`   10   point 224   20   Pi=cutspc(str(#pi)):Pi=left(Pi,1)+mid(Pi,3,*)   30   for N=1 to 1000   40     Tot1=Tot1+val(mid(Pi,N,1)):Tot2=Tot2+val(mid(Pi,N+1,1))   50     if Tot1 @ 111=0 then   60       :M=Tot1//111   70       :if 4*M*M=N then print N,M,Tot1,"tot1"   80     if Tot2 @ 111=0 then   90       :M=Tot2//111  100       :if 4*M*M=N then print N,M,Tot2,"tot2"  110   next NOKrunWords for fractionals 224 (Decimals for display 1078) 144     6       666    tot2OK`

This shows that n = 144 and m = 6, making 111*m = 666, the number of the beast according to Revelation (the Apocalypse), the last book of the New Testament.

The notation "tot2" indicates that the counting for n begins at the 1 after the decimal point, rather than the 3 at the beginning of pi.

The 144 digits involved that add up to 666 are given by:

`?mid(pi,2,144)141592653589793238462643383279502884197169399375105820974944592307816406286208998628034825342117067982148086513282306647093844609550582231725359`

 Posted by Charlie on 2012-05-13 12:51:51

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