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 Intersection of Bisectors (Posted on 2012-12-01)

Let Γ be a circle with center O. Let AC be a chord of  Γ (not containing O).
Let D be a point on chord AC (not A or C). The line through D and perpendicular to AC intersects Γ in points B1 and B2. Let H1 and H2 be the orthocenters of triangles
AB1C and AB2C respectively.

Define the point of intersection of the bisectors of angles H1B1O and H2B2O and

 See The Solution Submitted by Bractals Rating: 3.0000 (1 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
 From sketchpad. No proof. | Comment 1 of 2
Conjectures based on a Geometers Sketchpad drawing:

• The point of intersection is on the circle.
• It is independent of point D.
• It is the point where the perpendicular bisector of segment AC intersects the circle (on the same side of the center.)

 Posted by Jer on 2012-12-03 13:10:40

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